diff options
Diffstat (limited to 'packages/utils.py')
-rw-r--r-- | packages/utils.py | 103 |
1 files changed, 103 insertions, 0 deletions
diff --git a/packages/utils.py b/packages/utils.py new file mode 100644 index 00000000..204e5bf2 --- /dev/null +++ b/packages/utils.py @@ -0,0 +1,103 @@ +from django.db import connection +from django.db.models import Count, Max + +from operator import itemgetter + +from main.models import Package +from main.utils import cache_function +from .models import PackageGroup + +@cache_function(300) +def get_group_info(): + raw_groups = PackageGroup.objects.values_list( + 'name', 'pkg__arch__name').order_by('name').annotate( + cnt=Count('pkg'), last_update=Max('pkg__last_update')) + # now for post_processing. we need to seperate things out and add + # the count in for 'any' to all of the other architectures. + group_mapping = {} + for grp in raw_groups: + arch_groups = group_mapping.setdefault(grp[1], {}) + arch_groups[grp[0]] = {'name': grp[0], 'arch': grp[1], + 'count': grp[2], 'last_update': grp[3]} + + # we want to promote the count of 'any' packages in groups to the + # other architectures, and also add any 'any'-only groups + if 'any' in group_mapping: + any_groups = group_mapping['any'] + del group_mapping['any'] + for arch, arch_groups in group_mapping.iteritems(): + for grp in any_groups.itervalues(): + if grp['name'] in arch_groups: + found = arch_groups[grp['name']] + found['count'] += grp['count'] + if grp['last_update'] > found['last_update']: + found['last_update'] = grp['last_update'] + else: + new_g = grp.copy() + # override the arch to not be 'any' + new_g['arch'] = arch + arch_groups[grp['name']] = new_g + + # now transform it back into a sorted list + groups = [] + for val in group_mapping.itervalues(): + groups.extend(val.itervalues()) + return sorted(groups, key=itemgetter('name', 'arch')) + +@cache_function(300) +def get_differences_info(arch_a, arch_b): + # This is a monster. Join packages against itself, looking for packages in + # our non-'any' architectures only, and not having a corresponding package + # entry in the other table (or having one with a different pkgver). We will + # then go and fetch all of these packages from the database and display + # them later using normal ORM models. + sql = """ +SELECT p.id, q.id + FROM packages p + LEFT JOIN packages q + ON ( + p.pkgname = q.pkgname + AND p.repo_id = q.repo_id + AND p.arch_id != q.arch_id + AND p.id != q.id + ) + WHERE p.arch_id IN (%s, %s) + AND ( + q.id IS NULL + OR + p.pkgver != q.pkgver + OR + p.pkgrel != q.pkgrel + ) +""" + cursor = connection.cursor() + cursor.execute(sql, [arch_a.id, arch_b.id]) + results = cursor.fetchall() + to_fetch = [] + for row in results: + # column A will always have a value, column B might be NULL + to_fetch.append(row[0]) + # fetch all of the necessary packages + pkgs = Package.objects.in_bulk(to_fetch) + # now build a list of tuples containing differences + differences = [] + for row in results: + pkg_a = pkgs.get(row[0]) + pkg_b = pkgs.get(row[1]) + # We want arch_a to always appear first + # pkg_a should never be None + if pkg_a.arch == arch_a: + item = (pkg_a.pkgname, pkg_a.repo, pkg_a, pkg_b) + else: + # pkg_b can be None in this case, so be careful + name = pkg_a.pkgname if pkg_a else pkg_b.pkgname + repo = pkg_a.repo if pkg_a else pkg_b.repo + item = (name, repo, pkg_b, pkg_a) + if item not in differences: + differences.append(item) + + # now sort our list by repository, package name + differences.sort(key=lambda a: (a[1].name, a[0])) + return differences + +# vim: set ts=4 sw=4 et: |